Cctalk Serial Interface
Im looking fordward to integrate a coin acceptor into one of our divices. This specific coin acceptor CF7000 uses the ccTalk protocol
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I've been working with the default libraries provided from the supplier which I can use in C#, however i want to see if its possible Find and USE a C# Function equivalent to the cctalk protocol and if possible use it directly into my C# code
i have been using ILSpy to open and explore the libraries provided and found this function that opens the device so it can recieve coins and store them
in my code all i have to type is:
Jan 08, 2016 As a workaround the serial port must be reset at the runtime or some kind of translation hardware interface must be used. In exchange most micro controllers have special features to easily detect and use the 9’th bit signaling. CcTalk tutorial, ccTalk on Arduino nano part 5 bill acceptor example March 13, 2018; ccTalk tutorial. The identifying code of the RM5 CCTalk electronic coin mechanism is made of 15 digit as the two here after. Interface: CCTALK serial standard.
Aug 11, 2015 ccTalk tutorial, the hardware interface. Posted on August 11, 2015 February 6, 2018 by ccTalk tutorial. I don’t know a commercial interface from 3V TTL serial to ccTalk line. Palermo974Bruno says: May 24, 2017 at 11:21 am Thaks for the info.
in order for the device to call the following function inside the library
Now what i want to do is Find the CCTalk Protocol equivalent to this library function, in order for me to interact with the device, without the need to call the function from the library, however im not so sure this is easy or possible hopefully someone here might have a little bit more experience with this
1 Answer
In order to do what you want you have to communicate directly to the USB/Serial port and send directly the commands you want, and then build your own library or helper functions.
- Open serial port
- Generate the message to be sent, calculate checksum
- Write the message on the serial interface
- Listen for the answer if any.
Hope I've helped.